x^2+48x+495=0

Solution for x^2+48x+495=0 equation:

x^2+48x+495=0

a = 1; b = 48; c = +495;
Δ = b2-4ac
Δ = 482-4·1·495
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-18}{2*1}=\frac{-66}{2}
=-33
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+18}{2*1}=\frac{-30}{2}
=-15
$